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Solve the following system of equations below 4x+y=16 2x+3y=-2β
4 months ago
Q:
solve the following system of equations below 4x+y=16 2x+3y=-2β
Accepted Solution
A:
answer:x = 5y = -4steps:4x + y = 16multiply 2nd equation by 24x + 6y = -4subtract equations 0 -5y = 20-5y = 20y = 20 Γ· -5y = -4substitute y = -4 to find the value of x4x + (-4) = 164x - 4 = 164x = 20x = 5