Consider the graph of the line y = -x-4 and the point(-4,2).The slope of a line parallel to the given line isA point on the line parallel to the given line, passingthrough (-4,2), isThe slope of a line perpendicular to the given line isA point on the line perpendicular to the given linepassing through (-4, 2), is

Answer:-1y = -x -21y = x + 6Step-by-step explanation:Given line is y = - x - 4We know that the equation of a line is of the form y = mx + c where m is the slope of the line and c is a constantNow The slope of the given line is m = -1We know that the slope of any line parallel to the given line is same the original one Therefore the slope of the line parallel to the given line is -1Given the point is ( -4 , 2 ) and slope is  -1 We know that the equation of a line passing through the point (c , d) and slope m is [tex]y - d=m\times(x-c)[/tex]Here the equation is [tex]y-2=-1\times(x-(-4))[/tex]y = -x -2We know that if two lines with slopes m1 and m2 are perpendicular then m1m2 = -1Here m1 = -1 then m2 = 1Given the point is ( -4 , 2 ) and slope is  1    We know that the equation of a line passing through the point (c , d) and slope m is [tex]y - d=m\times(x-c)[/tex]Here the equation is [tex]y-2=1\times(x-(-4))[/tex]y = x + 6